0=x^2+24x+0.79

Solution for 0=x^2+24x+0.79 equation:

0=x^2+24x+0.79

We move all terms to the left:

0-(x^2+24x+0.79)=0

We add all the numbers together, and all the variables

-(x^2+24x+0.79)=0

We get rid of parentheses

-x^2-24x-0.79=0

We add all the numbers together, and all the variables

-1x^2-24x-0.79=0

a = -1; b = -24; c = -0.79;
Δ = b2-4ac
Δ = -242-4·(-1)·(-0.79)
Δ = 572.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{572.84}}{2*-1}=\frac{24-\sqrt{572.84}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{572.84}}{2*-1}=\frac{24+\sqrt{572.84}}{-2}
$